Potassium (at No. 19) and chlorine (at No. 17) form a compound. Explain the formation of the compound on the basis of :

(a) oxidation (b) reduction

(c) oxidising agent (d) reducing agent.

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Solution

2K + Cl₂→ 2KCl

Oxidation:In the electronic concept, oxidation is a process in which an atom or ion loses electron(s).
K → K⁺+ e^–

Reduction:In the electronic concept, reduction is a process in which an atom or ion accepts electron(s).
Cl₂+ 2e^–→ 2Cl^–

Oxidising agent
An oxidising agent oxidises other substances either by accepting electrons or by providing oxygen or an electronegative ion, or by removing hydrogen or an electropositive ion.
Cl₂+ 2e^–→ 2Cl^–

Reducing agent
A reducing agent reduces other substances either by providing electrons or by providing hydrogen or an electropositive ion, or by removing oxygen or an electronegative ion.
K → K⁺+ e^–

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Question 10

Hydrogen peroxide is .......

(a) an oxidising agent

(b) a reducing agent

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A = 2.80 V, B = 0.35 V, C = 0.01 V, D = - 0.43 V

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