Potassium dichromate and concentrated $H C l$ are heated together.
$K_{2} {C r}_{2} O_{7} + H C l ⟶ K C l + . . . . + . . . . . . + H_{2} O$

2 K_{2} {C r}_{2} O_{7} + 12 H C l \to 4 K C l + 4 C r {C l}_{3} + 7 H_{2} O + 3 {C l}_{2} ↑

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K_{2} {C r}_{2} O_{7} + 12 H C l \to 2 K C l + 2 C r {C l}_{3} + 7 H_{2} O + 3 {C l}_{2} ↑

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2 K_{2} {C r}_{2} O_{7} + 14 H C l \to 4 K C l + 4 C r {C l}_{3} + 7 H_{2} O + 3 {C l}_{2} ↑

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K_{2} {C r}_{2} O_{7} + 14 H C l \to 2 K C l + 2 C r {C l}_{3} + 7 H_{2} O + 3 {C l}_{2} ↑

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Solution

The correct option is D $K_{2} {C r}_{2} O_{7} + 14 H C l \to 2 K C l + 2 C r {C l}_{3} + 7 H_{2} O + 3 {C l}_{2} ↑$
Reaction of potassium dichromate and a conc. acid results in evolution of chlorine gas.
$K_{2} {C r}_{2} O_{7} + 14 H C l \to 2 K C l + 2 C r {C l}_{3} + 7 H_{2} O + 3 {C l}_{2} ↑$

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