Potassium permanganate on heating gives:
When heated, potassium permanganate decomposes according to the following equation:
2KMnO4→K2MnO4+MnO2+O2
Given that the molecular mass of potassium permanganate is 158, what volume of oxygen (measured at room temperature) would be obtained by the complete decomposition of 15.8 g of potassium permanganate? (Molar volume at room temperature is 24 liters.)