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Standard X

Chemistry

Mole Concept

Potassium sup...

Question

Potassium superoxide, $K O_{2}$ , is utilised in closed system breathing apparatus. Exhaled air contains $C O_{2}$ and $H_{2} O$ both of which are removed and the removal of water generates oxygen for breathing by the reaction: $4 K O_{2} (s) + 2 H_{2} O (l) \to 3 O_{2} (g) + 4 K O H (s)$ . The potassium hydroxide removes $C O_{2}$ from the appratus by the reaction: $K O H_{s w} + C O_{2} (g) \to K H C O_{3} (s)$ .
The mass of $K O_{2}$ generating $48$ g of oxygen is :

142 g

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153 g

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148 g

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150 g

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Solution

The correct option is D 142 g
$4 K O_{2} + 2 H_{2} O \to 3 O_{2} + 4 K O H$

4 moles of $K O_{2} \to$ 3 moles of $O_{2}$

molar mass of $K O_{2}$ = 71 g/mol

molar mass of $O_{2}$ = 32 g/mol

Mass of $K O_{2}$ = $\frac{4 \times 71}{3 \times 32} \times 48$ = 142 g

Hence, option A is correct.

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Similar questions

Q. A self-contained breathing' apparatus uses potassium superoxide,

K O_{2}

, to convert the carbon dioxide and water in exhaled air into oxygen, as shown by the equation:

4 K O_{2} (s) + 2 H_{2} O (g) 4 C O_{2} (g) \to 4 K H C O_{3} (s) + 3 O_{2} (g)

How many molecules of oxygen gas will be produced hem 0.0468 g of carbon dioxide that is exhaled in a typical breath?

$K O_{2}$ finds use in breathing equipment to safeguard the user to breathe in oxygen generated internally in the apparatus without being exposed to toxic fumes outside. The supply of oxygen is due to :

i.Slow decomposition of $K O_{2}$

ii.reaction of superoxide with moisture in the exhaled air

iii.reaction of $K O_{2}$ with $C O_{2}$ in the exhaled air

Q. Some older emergency oxygen masks containing potassium superoxide

(K O_{2}))

react with

C O_{2}

and water in exhaled air to produce oxygen according to the given equation.

4 K O_{2} + 2 H_{2} O + 4 C O_{2} \to 4 K H C O_{3} + 3 O_{2}

If a person exhales

0.667 g

C O_{2}

per minute, how many grams of

K O_{2}

are consumed in 5.0 minutes?

Q. Potassium superoxide (

{K O}_{2}

) is used in rebreathing gas masks to generate oxygen:

{K O}_{2} (s) + H_{2} O (l) ⟶ K O H (s) + O_{2} (g)

If a reaction vessel contains 0.158 mol

{K O}_{2}

and 0.10 mol

H_{2} O

, how many moles of

O_{2}

can be produced?

Q. Which of the following reactions of potassium super oxide supply oxygen gas in the breathing equipments used in space and submarines ?
(1) Reaction of superoxide with nitrogen in the exhaled air.
(2) Reaction of superoxide with moisture in the exhaled air.
(3) Reaction of superoxide with carbon dioxide in the exhaled air

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The correct option is D 142 g4KO2+2H2O→3O2+4KOH4 moles of KO2→ 3 moles of O2 molar mass of KO2 = 71 g/molmolar mass of O2 = 32 g/molMass of KO2 = 4×713×32×48 = 142 gHence, option A is correct.

The correct option is D 142 g
$4 K O_{2} + 2 H_{2} O \to 3 O_{2} + 4 K O H$

4 moles of $K O_{2} \to$ 3 moles of $O_{2}$

molar mass of $K O_{2}$ = 71 g/mol

molar mass of $O_{2}$ = 32 g/mol

Mass of $K O_{2}$ = $\frac{4 \times 71}{3 \times 32} \times 48$ = 142 g

Hence, option A is correct.