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Question

Potential difference across 4Ω resistance.
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Solution

Hint : Try to find current flowing in the circuit then use Ohm's Law for 4Ω resistor.

Step 1 : Find equivalent resistance of the circuit.
Given: Two resistors of 8Ω in parallel.
One resistance of 4Ω in series with above combination.
Net resistance of two two resistors of 8Ω
1Rnet= 1R1+1R2
1Rnet= 18+18
Rnet=4Ω
Equivalent resistance of whole circuit
Req=R4Ω+Rnet
Rnet=4Ω+4Ω=8Ω

Step 2 : Find current flowing in the circuit using Ohm's Law.
Ohm's Law for whole circuit V=IRnet
as V=8V and Rnet=8Ω
I=8V8Ω=1 A.
The same current is flowing throughout the circuit.

Step 3: Find potential difference across 4Ω resistor.

Applying Ohm's Law for 4Ω resistor we have
V=IR4Ω
V=1A×4Ω=4V

Final Step : The potential difference across the 4Ω resistor is 4V.

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