Potential difference across a capacitor of capacity 4μF is 1 kilovolt. The energy stored on capacitor is:
Given that,
Capacity of capacitor C=4μF
Voltage V=1kV
We know that,
Store energy is
E=12CV2
E=12×4×10−6×1×1×106
E=2J
Hence, the energy stored on capacitor is 2 J