The correct option is B 7.5 V
Resistance of diode in forward bias is very small compared to 10 kΩ and so it is neglected.
Req for the battery is 20 kΩ.
V=iReq
⇒ 30= i×20 kΩ⇒i=32 mA
Current divides equally into the two branches because of equal resistances, so through AB, the current is i2=34 mA
VAB=34 mA×10 kΩ=7.5 V