Potential drop across 5 - is 10 V- then EMF of the battery is

If voltage drop across 5 Ω is 10 V, then current in this branch, nbsp; i = Δ vR =105 =2 A for 15 Ω, nbsp; Δ v =i R = (2) (15) =30 V total drop =30+10 = 40 V ...

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Standard XIII

Physics

EMF and EMF Devices

Potential dro...

Question

Potential drop across $5 Ω$ is $10 V$ , then EMF of the battery is

12 V

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28 V

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30 V

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40 V

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Solution

The correct option is D $40 V$
If voltage drop across $5 Ω$ is $10 V$ , then
current in this branch,
$i = \frac{Δ v}{R} = \frac{10}{5} = 2 A$
for $15 Ω$ , $Δ v = i R = (2) (15) = 30 V$
total drop = $30 + 10 = 40 V$
Hence, EMF = $40 V$

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Potential drop across 5 Ω is 10 V, then EMF of the battery is

The correct option is D 40 VIf voltage drop across 5 Ω is 10 V, then current in this branch, i=ΔvR=105=2 A for 15 Ω, Δv=iR=(2)(15)=30 V total drop =30+10=40 V Hence, EMF = 40 V

Potential drop across $5 Ω$ is $10 V$ , then EMF of the battery is

The correct option is D $40 V$
If voltage drop across $5 Ω$ is $10 V$ , then
current in this branch,
$i = \frac{Δ v}{R} = \frac{10}{5} = 2 A$
for $15 Ω$ , $Δ v = i R = (2) (15) = 30 V$
total drop = $30 + 10 = 40 V$
Hence, EMF = $40 V$