Question

Potential due to a point mass $m$ at a distance $r$ is $V=-\frac{GM}{r}$.

Answer 1

$F=\frac{Gm\left(1\right)}{r^2}=$ Electric field

Potential $=+\int Edr$

$\Rightarrow P={\int }_0^2\frac{Gm}{r^2}dr$

$\Rightarrow P=\frac{-GM}{r}$

$\Rightarrow V=\frac{-GM}{r}$