Potential due to a thin ring at a distance x- V - -GM-R2 - x2

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Standard XII

Physics

Gravitational Potential

Potential due...

Question

Potential due to a thin ring at a distance $x$ .
$V = - \frac{G M}{\sqrt{R^{2} + x^{2}}}$

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Solution

Electric potential at $P$ due to each unit mass can be added directly as potential is scalar quantity.
So, $V = \frac{- G M}{\sqrt{R^{2} + x^{2}}}$

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Potential due to a thin ring at a distance x.V=−GM√R2+x2

Electric potential at P due to each unit mass can be added directly as potential is scalar quantity.So, V=−GM√R2+x2

Potential due to a thin ring at a distance $x$ .
$V = - \frac{G M}{\sqrt{R^{2} + x^{2}}}$

Electric potential at $P$ due to each unit mass can be added directly as potential is scalar quantity.
So, $V = \frac{- G M}{\sqrt{R^{2} + x^{2}}}$