You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

PE Diagram

Potential ene...

Question

Potential energy curve $U$ of a particle as function of the position of a particle is shown. The particle has total mechanical energy $E$ of $3.0$ joules. Then select correct alternative.

It can never be present at

x = 0 m

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

It can never be present at

x = 5 m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x = 2

its kinetic energy of

0 J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x = 1

its kinetic energy

3 J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B It can never be present at $x = 0 m$
Total mechanical energy $E = 3.0$ J
Total energy = Potential energy + kinetic energy

$∴$ $E = U + K$ where $K > 0$ (always)

From the graph, at $x = 0$ m, we get $U = 6$ J

$∴$ $3 = 6 + K$ $⟹ K = - 3$ J (Not possible)

Thus the particle can never be present at $x = 0 m$

Suggest Corrections

Similar questions

Q. A single conservative force

F (x)

acts on a particle that moves along the x-axis. The graph of the potential energy with x is given. At

x = 5 m

, the particle has a kinetic energy of

50 J

and its potential energy is related to position 'x' as

U = 15 + (x - 3)^{2}

Joule, where x is in meter. Find the mechanical energy of the particle.

Q. A given particle starts at

x = 1

on the potential function

U (x) = x^{2} - 10 x + 25

, where

U

is in Joules and

x

is in meters. It then moves down the potential gradient to

x = 3

where it has

4 J

of potential energy. If it started at rest, how much kinetic energy does it have as it passes through

x = 3

Q. The potential energy of a particle oscillating along x-axis is given as

U = 20 + (x - 2)^{2}

where

U

is in joules and

x

in meters. Total mechanical energy of the particle is

36 J

.
Maximum kinetic energy of the particle is

Q. A potential energy function is shown in graph. A particle moving in this potential field in positive x-direction possess 3 J of kinetic energy at x = 1 m. Where will it reverse its direction?

Q. The potential energy of a particle oscillating along

X -

axis is given as

U = 15 + 4 x + (2 x - 3)^{2}

, where

U

is in Joules and

x

in metres. Total mechanical energy of the particle is

36 J

. Mass of particle is

2 kg

. Then,

Join BYJU'S Learning Program

Potential energy curve U of a particle as function of the position of a particle is shown. The particle has total mechanical energy E of 3.0 joules. Then select correct alternative.

The correct option is B It can never be present at x=0mTotal mechanical energy E=3.0 J Total energy = Potential energy + kinetic energy ∴ E=U+K where K>0 (always)From the graph, at x=0 m, we get U=6 J∴ 3=6+K ⟹K=−3 J (Not possible)Thus the particle can never be present at x=0 m

Potential energy curve $U$ of a particle as function of the position of a particle is shown. The particle has total mechanical energy $E$ of $3.0$ joules. Then select correct alternative.