Potential energy of a body is given by V - a - x 12- b - x 6- - At x - x 0- equilibrium is stable - V - V 0- Then- forA- x V 0D- x - x 0- V - V 0

The correct option is C x gt; x_0, V gt; V_0The equation given in nbsp; question represent potential energy function. At stable nbsp;equilibrium posi ...

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Standard XII

Physics

Conservative and Non Conservative Forces

Potential ene...

Question

Potential energy of a body is given by $V = \frac{a}{x^{12}} - \frac{b}{x^{6}},$ . At $x = x_{0}$ , equilibrium is stable & $V = V_{0},$ . Then, for

x < x_{0}, V < V_{0}

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x > x_{0}, V > V_{0}

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x > x_{0}, V < V_{0}

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x < x_{0}, V = V_{0}

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Solution

The correct option is B $x > x_{0}, V > V_{0}$
The equation given in question represent potential energy function. At stable equilibrium position, potential energy is minimum and any distance less than or greater than equilibrium distance, potential energy is greater than potential energy at equilibrium.

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Potential energy of a body is given by V=ax12−bx6,. At x=x0, equilibrium is stable & V=V0,. Then, for

The correct option is B x>x0,V>V0The equation given in question represent potential energy function. At stable equilibrium position, potential energy is minimum and any distance less than or greater than equilibrium distance, potential energy is greater than potential energy at equilibrium.

Potential energy of a body is given by $V = \frac{a}{x^{12}} - \frac{b}{x^{6}},$ . At $x = x_{0}$ , equilibrium is stable & $V = V_{0},$ . Then, for