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Longest Chain Rule

Potential ene...

Question

Potential energy of a particle is given as $U (x) = 2 x^{3} - 9 x^{2} + 12 x$ where $U$ is in joule and $x$ is in metre. If the motion of a particle is S.H.M then find the approx. potential energy of the particle is:

- 36 J

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4 J

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5 J

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None of these

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Solution

The correct option is D None of these
$\begin{matrix} u = 2 x^{2} - 9 x^{2} + 12 x F = 6 x^{2} + 18 x + 12 = - 6 [x^{2} - 3 x + 2] = - 6 [(x - 2) (x - 1)] H e n c e, o p t i o n D i s c o r r e c t a n s w e r . \end{matrix}$

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Similar questions

U (x) = 2 x^{3} - 9 x^{2} + 12 x

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S . H . M

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U = 20 + (x - 2)^{2}

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