Question

Potential energy of a particle is given as $U\left(x\right)=2x^3-9x^2+12x$ where $U$ is in joule and $x$ is in metre. If the motion of a particle is $S.H.M$., then find the approx potential energy of the particle :-

• A. $-36J$
• B. $4J$
• C. $5J$
• D. None of these

Answer 1

Answer: (A)

$-36J$

$6x^2-18n+12=0$
$x^2-3x+2=0$
$x^2-2x-x+2=0$
$x(x-2)+1(x-2)=0$
$(x-2)(x-1)$
$x=2$
$4\left(x\right)=16-36+29$
$=4J$
$4\left(x\right)=2-9+12$
$=5J$