You visited us 1 times! Enjoying our articles? Unlock Full Access!

SHM expression

Potential ene...

Question

Potential energy U varies with distance x as $U = \frac{A x^{1 / 2}}{X^{2} + B}$ where A and B are constant. The dimensional formula for $A \times B$ is

$M^{1} L^{\frac{7}{2}} T^{- 2}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$M^{1} L^{\frac{11}{2}} T^{- 2}$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

$M^{1} L^{\frac{5}{2}} T^{- 2}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$M^{1} L^{\frac{9}{2}} T^{- 2}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B
$M^{1} L^{\frac{11}{2}} T^{- 2}$

$X^{2} has dimension of L^{2} t h e n M L^{2} T^{- 2} = \frac{A \times L^{\frac{1}{2}}}{L^{2}} A = M L^{\frac{7}{2}} 7^{- 2} A \times B = M L^{\frac{11}{2}} T^{- 2}$

Suggest Corrections

Similar questions

x

\frac{A x^{1 / 2}}{x^{2} + B}

A

B

A \times B

x

U = \frac{A x^{1 / 2}}{x^{2} + B}

x

U = \frac{A \sqrt{x}}{x^{2} + B}

a

b

F = a \sqrt{x} + b t^{2}

F

x

t

U = \frac{α \sqrt{y}}{y + β}

α

β

y

(α \times β)

Join BYJU'S Learning Program