Question

Power of $10W$ is emitted by a loudspeaker. The sound intensity radiated by it at a distance of $3m$ is $2W/m^2$. If the intensity of loudspeaker is doubled the intensity at $6m$ will be

• A. $1W/m^2$
• B. $4W/m^2$
• C. $0.5W/m^2$
• D. $2W/m^2$

Answer 1

The correct option is A $1W/m^2$

$\frac{k\frac{10}{3^2}}{k\frac{20}{6^2}}=\frac{2}{x}$
$x=1W{m}^{-2}$