Power of a convex lens of focal length 50cm is:

-2D

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- \frac{1}{2}

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\frac{1}{2}

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Solution

The correct option is D 2D
$\begin{matrix} Focal length of convex lens = + 50 c m Power = \frac{100}{f (c m)} = \frac{100}{+ 50} = 2 D option C is correct \end{matrix}$

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Power of a convex lens of focal length 50cm is:

The correct option is D 2D Focal length of convex lens =+50 cm Power =100f( cm)=100+50=2D option C is correct

The correct option is D 2D
$\begin{matrix} Focal length of convex lens = + 50 c m Power = \frac{100}{f (c m)} = \frac{100}{+ 50} = 2 D option C is correct \end{matrix}$