Power supplied to a particle of mass 2 kg varies with time as p=3t22 watt. Here 't' is in second. If velocity of particle at t = 0 is v = 0. The velocity of particle at time t = 2 second will be
A
1 m/s
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B
4 m/s
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C
2 m/s
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D
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Solution
The correct option is C 2 m/s kf−ki=∫20Pdt⇒12mv2=∫2032t2dt⇒v2=[t32]20⇒v=2m/s