PQ = 1.28 cm; PR = 2.56 cm,
PM =0.16 cm; PN =0.32 cm.

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Solution

PQ = 1.28, PM =0.16
$\Rightarrow$ MQ = PQ - PM = 1.28 - 0.16 = 1.12
NR = PR - PN = 2.56 - 0.32 = 2.24
Now
$\frac{P M}{M Q} = \frac{0.16}{1.12} = \frac{1}{7}$

$\frac{P N}{N R} = \frac{0.32}{2.24} = \frac{1}{7}$

$∴ \frac{P M}{M Q} = \frac{P N}{N R}$ $[E a c h r a t i o = \frac{1}{7}]$
$\Rightarrow$ By the converse of Basic Proportionality Theorem,
$M N ∥ Q R$

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PQ = 1.28 cm; PR = 2.56 cm,PM =0.16 cm; PN =0.32 cm.

PQ = 1.28, PM =0.16 ⇒ MQ = PQ - PM = 1.28 - 0.16 = 1.12 NR = PR - PN = 2.56 - 0.32 = 2.24 Now PMMQ=0.161.12=17 PNNR=0.322.24=17 ∴PMMQ=PNNR [Eachratio=17] ⇒ By the converse of Basic Proportionality Theorem, MN∥QR

PQ = 1.28 cm; PR = 2.56 cm,
PM =0.16 cm; PN =0.32 cm.