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Question

PQ and PR are the tangents to a circle with centre O. If P=45O. Find QOR.

A
90o
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B
80o
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C
110o
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D
100o
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Solution

The correct option is C 100o
Given,
PQ and PR are tangents to the circle.
And P=45O
Tangents are perpendicular to radius at the point of contact.
Therefore, PQO=ORP=90

Sum of all the four angles of a quadrilateral is 360
So in quadrilateral QORP,
PQO+QOR+ORP+RPQ=360

90+O+90+P=360

180+O+45O=360

95O=360180

95O=180

O=59×180

O=100

QOR=O=100

Hence, OpD is correct.

839744_598340_ans_8a199ba7c08447cc991bd155735b5ca2.png

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