PQ and PR are two tangents drawn from a point P. If centre 'O' of the circle and P are joined, then ∠OPR:∠OPQ =.
A
2:1
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B
1:1
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C
1:2
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D
4:1
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Solution
The correct option is B1:1 Join the points OP, OQ and OR. In △OPQ and △OPR,OP=OP (common side) OQ=OR (radii of the same circle)∠OQP=∠ORP=90∘(Tangent is perpendicular to the radius)∴ΔOQP≅ΔORP (RHS congruency)