Question

PQ = BR

If the above statement is true then mention answer as 1, else mention 0 if false.

Answer 1

Given: ABCD is a square.
thus, $AB=BC$
$AP=BQ$ (Given)
$AB-AP=BC-BQ$
$PB=CQ$ (I)
Now, In $△PBQ$ and $△CQR$,
$\angle PBQ=\angle QCR$ (Each ${90}^{\circ }$)
$PB=CQ$ (From I)
$BP=CR$ (Given)
thus, $△PBQ\cong △CQR$ (SAS rule)
or, $PQ=QR$ (By cpct)