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Question

PQ is a chord of length 8cm of a circle of radius 5cm and center O. The tangents at P and Q intersect at a point T. Find the length TP.
1446279_f41124509916402d8f927b06a8a938d2.png

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Solution

Join OT

In ΔOPT

OT2=OP2+PT2(1)

OT is perpendicular bisector to PQ let they met at S

SP=4cm

By pythagorean theorm

SO=3cm

By property associated with altitudes of Right angled triangle

ΔOPTΔPSO

OSSP=OPPT34=5TPTP=6.66 cm

1220750_1446279_ans_6b1be33c9048422193e5b6963f8d04dc.png

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