PQ is a line parallel to side BC and passing through vertex A of a triangle ABC. If BE || AC and CF || AB meet PQ at E and F respectively. If the base and altitude of ΔABC are 6 cm and 8 cm respectively, the area of ΔACF is ___.
CF when drawn parallel to AB, forms parallelogram ABCF.
AC is the diagonal of the parallelogram that divides ABCF into 2 equal triangles ABC and ACF.
So, Area of ΔACF = Area of ΔABC = 12×6×8=24 cm2