Question

PQ is a tower standing on a horizontal plane, Q being its foot. A and B are two points on the plane such that the angle QAB is 90${}^o$ and AB is 40m. It is found that $cotPAQ=\frac{3}{10}$ and $cotPBQ=\frac{1}{2}$. Show that the height of the tower is 100 m.

Answer 1

Use pythagoares theorm to find the answer