Question

PQR is a right angled isosceles triangle, right angle at Q, then prove that $P{R}^2=2P{Q}^2$

Answer 1

R.E.F image

Given $\angle Q={90}^o$

$PQ=QR$____(1)

$P{Q}^2+Q{R}^2=P{R}^2$ (Pythagoras theorem)

Using $e{q}^n$ (1)

$P{R}^2=2P{Q}^2=2Q{R}^2$