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Question

PQR is a triangle right angled at P and M is a point on QR such that PMQR show that PM2=QM.MR.

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Solution

If a perpendicular is drawn from the vertex of the right angle to the
hypotenuse then triangle on high side of the perpendicular are same.
So, ΔPMRΔQMP
If two triangles are similar then the ratio is
PMQM=MRMPPM×MP=MR×QMPM=MR×QM

1196970_1315177_ans_86a98958d4fb483f87b084d0415d0615.PNG

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