Question

Question 1
PQR is a triangle, right angled at P. If PQ = 10 cm and PR = 24 cm, find QR.

Answer 1

Given: PQ = 10 cm, PR =24cm
Let QR be x cm.
In right angled triangle QPR,
$(Hypotenuse{)}^2=(Base{)}^2+(Perpendicular{)}^2$
[By Pythagoras theorem]

$\Rightarrow (QR{)}^2=(PQ{)}^2+(PR{)}^2\Rightarrow x^2=(10{)}^2+(24{)}^2\Rightarrow x^2=100+576=676\Rightarrow x=\sqrt{676}=26cm\text{Thus, the length of QR is 26 cm.}$