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Question

PQR is an isosceles triangle whose equal sides PQ and PR are at right angles. S and T are points on PQ such that QS=6SP and QT=2TP.PRS=θ,PRT=ϕ

A
sin2ϕ=3/5
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B
2ϕ+θ=45o
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C
sin2θ=3/5
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D
sinϕ+cosϕ=410
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Solution

The correct options are
A sin2ϕ=3/5
B 2ϕ+θ=45o
D sinϕ+cosϕ=410
Let equal sides be a
tanθ=SPPR=a2a=12
sinθ=150
tanϕ=PTPR=a3a=13
sinϕ=110
sin2ϕ=2tanϕ1+tan2ϕ=2×131+19=35
cos2ϕ=45
sinϕ+cosϕ=110+310=410
sin(2ϕ+θ)=sin(2ϕ)cosθ+cos2ϕsinθ=35×350+45×150=12
Hence 2ϕ+θ=sin112=45

640974_192674_ans_b0cd83f319b2405784d6fb0956f10a70.png

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