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Question

PQRS is a cyclic quadrilateral and PQ is the diameter of the circle IfQPR=35 then the value of PSR IS equal to
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A
125
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B
135
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C
145
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D
155
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Solution

The correct option is C 125
QPR=35o [ Given ]
PRQ=90o [ Angle inscribed in semi-circle ]
QPR+PRQ+RQP=180o [ Sum of interior angles of triangle is 180o ]
35o+90o+RQP=180o
125o+RQP=180o
RQP=55o
PSR+RQP=180o [ Sum of pair of opposite angles of cyclic quadrilateral is 180o ]
PSR+55o=180o
PSR=180o55o
PSR=125o

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