PQRS is a isosceles trapezium with $P Q ∥ R S$ , if P $= 60$ , then Q equals to

120

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30

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60

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150

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Solution

The correct option is B $60$

In an isosceles trapezium base angles are of same measure.
$∴ ∠ P = ∠ Q$
Given, $∠ P = 60^{o}$
$∴ ∠ Q = 60^{o}$
Option C is correct.

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Similar questions

P Q R S

P Q ∥ S R

∠ P = 30^{o}

∠ Q = 50^{o}

∠ R

∠ S

PQ is a tangent to a circle with centre O at the point P. If $Δ$ OPQ is an isosceles triangle, then $∠$ OQP is equal to

(a) $30^{o}$ (b) $45^{o}$ (c) $60^{o}$ (d) $90^{o}$

P Q R S

P Q = 8

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∠ P = 60^{\circ}, ∠ Q = 45^{\circ}, ∠ R = 60^{\circ}

In an isosceles triangle PQR, PQ = PR and angle Q measures 40^o then the measure of angle P is:

∠ P = 60^{\circ}

45^{\circ}, 135^{\circ}, 120^{\circ}

60^{\circ}, 120^{\circ}, 120^{\circ}

60^{\circ}, 135^{\circ}, 135^{\circ}

45^{\circ}, 135^{\circ}, 135^{\circ}

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