Question

$PQRS$ is a parallelogram of area $120c{m}^2.PS=10cm,PQ=15cm$ Find $SM$.

Answer 1

Area of parallelogram $=120c{m}^2=15\times PM⟹PM=8cm$

Now in $△PMS$

$P{S}^2=S{M}^2+P{M}^2$

${10}^2=S{M}^2+8^2$

$⟹SM={10}^2-8^2=6cm$