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Standard IX

Mathematics

Opposite Sides of a Parallelogram Are Equal

PQRS is a par...

Question

PQRS is a parallelogram. PM is the height from P to $¯ ¯¯¯¯¯¯ ¯ S R$ and PN is the height from P to $¯ ¯¯¯¯¯¯¯ ¯ Q R$ . If SR=12 cm and PM=7.6 cm. Find the area of the parallelogram PQRS.

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Solution

PQRS is a parallelogram,
we know,
area of PQRS parallelogram = base * height
= length of SR * length of PM
GIVEN:-
length of SR = 12cm ,
length of PM = 7.6 cm
so, area of PQRS = 12cm * 7.6 cm
= 91.2 cm²

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Q. In given figure

P Q R S

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Q. PQRS is a parallelogram. QM is the perpendicular height from Q to SR and QN is the perpendicular height from Q to PS. If SR

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PQRS is a parallelogram (see the given figure). QM is the height from Q to SR and QN is the height from Q to PS. If SR = 12 cm and QM = 7.6 cm. Find:

(a) the area of the parallelogram PQRS

(b) QN, if PS = 8 cm

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and

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Q N

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P Q R S

is a parallelogram (Fig

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and

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is the height from

Q

P S

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(b)

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PQRS is a parallelogram. PM is the height from P to ¯¯¯¯¯¯¯¯SR and PN is the height from P to ¯¯¯¯¯¯¯¯¯QR. If SR=12 cm and PM=7.6 cm. Find the area of the parallelogram PQRS.

PQRS is a parallelogram, we know,area of PQRS parallelogram = base * height = length of SR * length of PM GIVEN:- length of SR = 12cm ,length of PM = 7.6 cm so, area of PQRS = 12cm * 7.6 cm = 91.2 cm²

PQRS is a parallelogram. PM is the height from P to $¯ ¯¯¯¯¯¯ ¯ S R$ and PN is the height from P to $¯ ¯¯¯¯¯¯¯ ¯ Q R$ . If SR=12 cm and PM=7.6 cm. Find the area of the parallelogram PQRS.

PQRS is a parallelogram,
we know,
area of PQRS parallelogram = base * height
= length of SR * length of PM
GIVEN:-
length of SR = 12cm ,
length of PM = 7.6 cm
so, area of PQRS = 12cm * 7.6 cm
= 91.2 cm²