Given PQRS is a parallelogram X and Y are mid points of PQ and SR respectively and PS || XY || QR
Construction Draw SM⊥PQ
Now Area || gm XQRY Area || gm PQRS = XQ×SMPQ×SM=12PQPQ=12
\therefore Area || gm XQRY = 12 area || gm PQRS = 12×24cm2=12 cm2
Now area || gm XQYS area || gm XQRY = XQ×SMXQ×SM=1
∴ area || gm XQYS = area || gm XQRY = 12 cm2.