Question

PQRS is a smallest square whose vertices are on the opposite sides of the square ABCD. The ratio of the area of $\square$ PQRS to $\square$ ABCD is

• A. $1:2$
• B. $1:\sqrt{2}$
• C. $1:3$
• D. $2:3$

Answer 1

Answer: (A)

$1:2$

$\frac{AreaofsquarePQRS}{AreaofsquareABCD}$
$=\frac{\frac{a^2}{2}}{a^2}=\frac{1}{2}$