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Question

PQRS is a square of length a, a natural number >1. Let L1,L2,L3,L4be points on QR such that QL1=L1L2=L2L3=L3L4.=1 and M1,M2,M3 be points on RS such that RM1=M1M2=M2M3..... . .=1. Then, a1n=1(PL2n+LnM2n) is equal to?

A
½ x a x (a-1)2
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B
½ x a x(a-1)x(4a-1)
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C
½ x(a-1)x(2a-1)x(4a-1)
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D
½ x(a+1)x(2a-1)x(4a-1)
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Solution

The correct option is B ½ x a x(a-1)x(4a-1)

option (b)

Assume a square of side 2 as follows with L1 as the midpoint of side QR and M1 as the mid-point of side RS

At n=1, the expression yields a value 5+2=7

Look in the answer options for 7, when n=1. Eliminate those answer options where this is not obtained

12×a×(a1)2 = 1

12 × a×(a-1)×(4a-1)= 7

12 ×(a-1)×(2a-1)×(4a-1)=212

12 ×(a+1)×(2a-1)×(4a-1)=632

a2×2n2 = 8

answer is option (b)


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