PQRS is a square of length a, a natural number >1. Let L1,L2,L3,L4…be points on QR such that QL1=L1L2=L2L3=L3L4….=1 and M1,M2,M3 be points on RS such that RM1=M1M2=M2M3..... . .=1. Then, a−1n=1∑(PL2n+LnM2n) is equal to?
option (b)
Assume a square of side 2 as follows with L1 as the midpoint of side QR and M1 as the mid-point of side RS
At n=1, the expression yields a value 5+2=7
Look in the answer options for 7, when n=1. Eliminate those answer options where this is not obtained
12×a×(a−1)2 = 1
12 × a×(a-1)×(4a-1)= 7
12 ×(a-1)×(2a-1)×(4a-1)=212
12 ×(a+1)×(2a-1)×(4a-1)=632
a2×2n2 = 8
answer is option (b)