Question

PQRS is a square with diagonals PR and SQ meeting at O. Find the value of 'x + 10'. [2 Marks]

Answer 1

Given:
$OS=5x-4$
$OR=3x+2$
Diagonals of a square are equal and bisect each other.

So,
$5x-4=3x+2$
$\Rightarrow 2x=6$
$\Rightarrow x=3$ [1 Mark]

Therefore, the value of x + 10 = 3 + 10 = 13. [1 Mark]