Pragya Raptor code around a circular path of radius 4 cm and cut off the length required to the end. Then she wrapped it around a square box of side 4 cm did she have any code left?

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Solution

The perimeter of circle is $2 π 4 = 8 \times 3.14 = 25.12 c m$
The perimeter of square is $4 (4) = 16 c m$
The remaining rope is $25.12 - 16 = 9.12 c m$

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Pragya wrapped a cord around a circular pipe of radius 4 cm (adjoining figure) and cut off the length required of the cord. Then she wrapped it around a square box of side 4 cm (also shown). Did she have any cord left? (π= 3.14).

Q. Pragya wrapped a cord around a circular pipe of radius 4 cm (adjoining figure) and cut off the length required of the cord. Then she wrapped it around a square box of side 4 cm (also shown). Did she have any cord left?

(π = 3.14)

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Pragya Raptor code around a circular path of radius 4 cm and cut off the length required to the end. Then she wrapped it around a square box of side 4 cm did she have any code left?

The perimeter of circle is 2π4=8×3.14=25.12cmThe perimeter of square is 4(4)=16cmThe remaining rope is 25.12−16=9.12cm

The perimeter of circle is $2 π 4 = 8 \times 3.14 = 25.12 c m$
The perimeter of square is $4 (4) = 16 c m$
The remaining rope is $25.12 - 16 = 9.12 c m$