Question 8

Pragya wrapped a cord around a circular pipe of radius 4 cm (adjoining figure) and cut off the length required of the cord. Then she wrapped it around a square box of side 4 cm (also shown) Did she have any cord left?
$(T a k e π = 3.14)$

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Solution

Radius of pipe = 4 cm
Length of cord around circular pipe = $2 π r$
$= 2 \times 3.14 \times 4 = 25.12 c m$
Again, length of cord around a square = $4 \times s i d e$
$= 4 \times 4 = 16 c m$
Remaining cord = Cord wrapped on circular pipe - Cord wrapped on square
= 25.12 - 16 = 9.12 cm
Thus, she is left with 9.12 cm cord.

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Question 8 Pragya wrapped a cord around a circular pipe of radius 4 cm (adjoining figure) and cut off the length required of the cord. Then she wrapped it around a square box of side 4 cm (also shown) Did she have any cord left? (Take π=3.14)

Radius of pipe = 4 cm Length of cord around circular pipe = 2πr = 2×3.14×4 = 25.12 cm Again, length of cord around a square = 4×side = 4×4 = 16 cm Remaining cord = Cord wrapped on circular pipe - Cord wrapped on square = 25.12 - 16 = 9.12 cm Thus, she is left with 9.12 cm cord.

Question 8

Pragya wrapped a cord around a circular pipe of radius 4 cm (adjoining figure) and cut off the length required of the cord. Then she wrapped it around a square box of side 4 cm (also shown) Did she have any cord left?
$(T a k e π = 3.14)$