Pragya wrapped a cord around a circular pipe of radius 4 cm (adjoining figure) and cut off the length required of the cord. Then she wrapped it around a square box of side 4 cm (also shown). Did she have any cord left? (π= 3.14).

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Solution

Perimeter of the square = 4 × Side of the square = 4 × 4 = 16 cm

Perimeter of circular pipe = 2πr = 2 × 3.14 × 4 = 25.12 cm

Length of chord left with Pragya = 25.12 − 16 = 9.12 cm

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Pragya wrapped a cord around a circular pipe of radius 4 cm (adjoining figure) and cut off the length required of the cord. Then she wrapped it around a square box of side 4 cm (also shown) Did she have any cord left?
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Pragya wrapped a cord around a circular pipe of radius 4 cm (adjoining figure) and cut off the length required of the cord. Then she wrapped it around a square box of side 4 cm (also shown). Did she have any cord left? (π= 3.14).

Perimeter of the square = 4 × Side of the square = 4 × 4 = 16 cm Perimeter of circular pipe = 2πr = 2 × 3.14 × 4 = 25.12 cm Length of chord left with Pragya = 25.12 − 16 = 9.12 cm

Perimeter of the square = 4 × Side of the square = 4 × 4 = 16 cm

Perimeter of circular pipe = 2πr = 2 × 3.14 × 4 = 25.12 cm

Length of chord left with Pragya = 25.12 − 16 = 9.12 cm