Pragya wrapped a cord around a circular pipe of radius 4 cm (adjoining figure) and cut off the length required of the cord. Then she wrapped it around a square box of side 4 cm (also shown). Did she have any cord left? $(π = 3.14)$

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Solution

Perimeter of the square = 4 $\times$ Side of the square = 4 $\times$ 4 = 16 cm
Perimeter of circular pipe = $2 π r = 2 \times 3.14 \times 4 = 25.12 c m$
Length of chord left with Pragya = 25.12 - 16 = 9.12 cm

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Pragya wrapped a cord around a circular pipe of radius 4 cm (adjoining figure) and cut off the length required of the cord. Then she wrapped it around a square box of side 4 cm (also shown). Did she have any cord left? (π= 3.14).

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Pragya wrapped a cord around a circular pipe of radius 4 cm (adjoining figure) and cut off the length required of the cord. Then she wrapped it around a square box of side 4 cm (also shown). Did she have any cord left? (π=3.14)

Perimeter of the square = 4 × Side of the square = 4 × 4 = 16 cm Perimeter of circular pipe = 2πr=2×3.14×4=25.12 cm Length of chord left with Pragya = 25.12 - 16 = 9.12 cm

Pragya wrapped a cord around a circular pipe of radius 4 cm (adjoining figure) and cut off the length required of the cord. Then she wrapped it around a square box of side 4 cm (also shown). Did she have any cord left? $(π = 3.14)$

Perimeter of the square = 4 $\times$ Side of the square = 4 $\times$ 4 = 16 cm
Perimeter of circular pipe = $2 π r = 2 \times 3.14 \times 4 = 25.12 c m$
Length of chord left with Pragya = 25.12 - 16 = 9.12 cm