Pranay's father is 7 times his age now . Two years later his father will be 5 times as old as his son will be . Find their present ages ?

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Solution

Let pranay's age be x
his father's age =7x
two years later
5(x+2)=7x+2
5x+10=7x+2
8=2x
x=4
pranay's age is 4years
and his fathers =4×7=28years

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Pranay's father is 7 times his age now . Two years later his father will be 5 times as old as his son will be . Find their present ages ?

Let pranay's age be x his father's age =7x two years later 5(x+2)=7x+2 5x+10=7x+2 8=2x x=4 pranay's age is 4years and his fathers =4×7=28years

Let pranay's age be x
his father's age =7x
two years later
5(x+2)=7x+2
5x+10=7x+2
8=2x
x=4
pranay's age is 4years
and his fathers =4×7=28years