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Standard VI

Mathematics

Word Problems

Praveen has ...

Question

Praveen has $R s . 4, 662$ in the form of $2, 5$ and $10$ rupee notes. If these notes are in the ratio of $3 : 5 : 8$ , the number of five rupees notes with him is

336

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250

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84

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210

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Solution

The correct option is C $210$
Let the number of $2, 5$ and $10$ rupees notes be $3 x, 5 x$ and $8 x$ .
Then, sum of their values $= 3 x \times 2 + 5 x \times 5 + 8 x \times 10 = 111 x$
$∴ 111 x = 4662$
$∴ x = \frac{4662}{111} = 42$
Hence, the number of $5$ rupees notes $= 42 \times 5 = 210$ .

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Praveen has Rs.4,662 in the form of 2,5 and 10 rupee notes. If these notes are in the ratio of 3:5:8, the number of five rupees notes with him is

The correct option is C 210Let the number of 2,5 and 10 rupees notes be 3x,5x and 8x.Then, sum of their values =3x×2+5x×5+8x×10=111x∴111x=4662 ∴x=4662111=42Hence, the number of 5 rupees notes =42×5=210.

Praveen has $R s . 4, 662$ in the form of $2, 5$ and $10$ rupee notes. If these notes are in the ratio of $3 : 5 : 8$ , the number of five rupees notes with him is

The correct option is C $210$
Let the number of $2, 5$ and $10$ rupees notes be $3 x, 5 x$ and $8 x$ .
Then, sum of their values $= 3 x \times 2 + 5 x \times 5 + 8 x \times 10 = 111 x$
$∴ 111 x = 4662$
$∴ x = \frac{4662}{111} = 42$
Hence, the number of $5$ rupees notes $= 42 \times 5 = 210$ .