Question

Praveen wanted to make a temporary shelter for her car, by making a box-like structure with tarpaulin that covers all the four sides and the top of the car (with the front face as a flap which can be rolled up). Assuming that the stitching margins are very small, and therefore negligible, how much tarpaulin would be required to make the shelter of height $2.5m$, with base dimensions $4m\times 3m$?

Answer 1

Sol $\to$ Given $\to$ Length of box (e) = 4 m

Breadth of box (b) = 3 m

Height of box (h) = 2.5 m

Required shelter for car $=$ cuboid box with

$l,b,h$ dimensions arid

open at bottom

$\therefore$ Required tarpaulin $=$ Total surface area of 5 focus of

cuboid

$=(l\times b)+2\times (b\times h)+2\times (l\times h)$

$=(4\times 3)+2\times (3\times 2.5)+2\times (4\times 2.5)$
$=12+15+20$
$=47m^2$