The correct option is B III>II>I
More the % s-character, more will be the electronegativity of the attached carbon. Hence more will be the strength of −I effect.
−Csp≡N>−Csp2H=NH>−Csp3H2−NH2
Therefore, the correct order for the −I strength is:
−C≡N>−CH=NH>−CH2−NH2
Hence option (b) is the correct answer.