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Question

Predict the correct order of −I strength for the following groups:
I.−CH2NH2II.−CH=NHIII.−CN

A
I>II>III
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B
III>II>I
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C
I>III>II
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D
III>I>II
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Solution

The correct option is B III>II>I
More the % s-character, more will be the electronegativity of the attached carbon. Hence more will be the strength of I effect.
CspN>Csp2H=NH>Csp3H2NH2
Therefore, the correct order for the I strength is:
CN>CH=NH>CH2NH2

Hence option (b) is the correct answer.

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