Predict the effect upon the following reaction equilibria of increased pressure.
$(1) H_{2} O (g) ⇌ H_{2} (g) + \frac{1}{2} O_{2} (g) (2) C a C O_{3} (s) ⇌ C a O (s) + C O_{2} (g) (3) C (s) + H_{2} O (g) ⇌ H_{2} (g) + C O (g)$

Left, Left, Left

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Right, Right, Right

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Left, Right, Left

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Solution

The correct option is A Left, Left, Left
On increasing pressure, the concentration of species will increase.
Then the equilibrium will shift towards the direction where the concentration or number of moles will be less.
In all the reaction the number of moles of species is less in reactant side. So, the equilibrium will shift towards left.

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Similar questions

Q. Predict the effect upon the following reaction equilibria of increased pressure.

(1) H_{2} O (g) ⇌ H_{2} (g) + \frac{1}{2} O_{2} (g) (2) C a C O_{3} (s) ⇌ C a O (s) + C O_{2} (g) (3) C (s) + H_{2} O (g) ⇌ H_{2} (g) + C O (g)

Q. For the reaction,

C (s) + H_{2} O (g) ⇌ H_{2} (g) + C O (g)

, by increasing pressure following equilibrium :

C_{(s)} + H_{2} O_{(g)} \to C O (g) + H_{2} (g)

The pressure on the system is increased in the above reaction then:

Q. If pressure increases then its effect on given equilibrium

C (s) + H_{2} O (g) ⇌ C O (g) + H_{2} (g)

It is shifted in:

Calculate the equilibrium constant ( $K_{p}$ ) for the reaction, $C (s) + C O_{2} (g) ⇌ 2 C O (g)$ , at $1300 K$ from the following data:
$C (s) + H_{2} O (g) ⇌ C O (g) + H_{2} (g); K_{p} (1300 K) = 3.9 a t m$

$H_{2} (g) + C O_{2} (g) ⇌ C O (g) + H_{2} O (g); K_{p} (1300 K) = 0.623 a t m$

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Predict the effect upon the following reaction equilibria of increased pressure. (1) H2O(g)⇌H2(g)+12O2(g)(2) CaCO3(s)⇌CaO(s)+CO2(g)(3) C(s)+H2O(g)⇌H2(g)+CO(g)

Predict the effect upon the following reaction equilibria of increased pressure.
$(1) H_{2} O (g) ⇌ H_{2} (g) + \frac{1}{2} O_{2} (g) (2) C a C O_{3} (s) ⇌ C a O (s) + C O_{2} (g) (3) C (s) + H_{2} O (g) ⇌ H_{2} (g) + C O (g)$