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Question

Predict the formula of a compound formed between a metal 'M' which has 1st, 2nd, 3rd IP values as 518, 7314, 9820 KJmol−1 respectively and a halogen 'X'.

A
MX2
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B
M2X3
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C
MX3
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D
MX
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Solution

The correct option is D MX
Alkali metals have low first ionization energies and relatively higher second and third ionization energies because the electron have to be remover from a stable octet.

As in the given question, there is more difference in the values of first and second ionization energies i.e. the metal has 1 valence electron,

formula of the compound will be MX.

Option D is correct.



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