Predict the nature of the salt obtained in the reaction given below:

${CH}_{3} COOH (aq) + NaOH (aq)$ $\to$ ${CH}_{3} COONa (s) + H_{2} O (l)$

Acidic

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Neutral

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Basic

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Cannot be determined.

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Solution

The correct option is C Basic
Acetic acid is a weak acid and sodium hydroxide is a strong base. Therefore, the salt formed will be of basic nature.

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Similar questions

{CH}_{3} COOH (aq) + NaOH (aq)

\to

{CH}_{3} COONa (s) + H_{2} O (l)

C H_{3} C O O C_{2} H_{5} (a q) + N a O H (a q) ⟶ C H_{3} C O O N a (a q) + C_{2} H_{5} O H (a q)

H_{2} O_{(l)} + H_{2} O_{(l)} ⇌ H_{3} O_{(a q)}^{+} + O H_{(a q)}^{-}

V^{2 +} (a q) + V O^{2 +} (a q) + 2 H^{+} (a q) \to 2 V^{3 +} (a q) + H_{2} O (l); E_{c e l l}^{0} = 0.616 V

V^{3 +} (a q) + A g^{+} (a q) + H_{2} O (l) \to V O^{2 +} (a q) + 2 H^{+} (a q) + A g (s); E_{c e l l}^{0} = 0.439 V

E^{0}

V^{3 +} (a q) + e \to V^{2 +} (a q)

(E_{A g^{+} (a q) / A g (s)}^{0} = 0.799 V)

H_{2} S O_{4} (a q) + H_{2} O (l) ⇌ H_{3} O^{+} (a q) + H S O_{4}^{-} (a q)

H C_{2} H_{3} O_{2} (a q) + H_{2} O (l) ⇌ H_{3} O^{+} (a q) + C_{2} H_{3} O_{2}^{-} (a q)

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