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Multi-Electron Configurations and Orbital Diagrams

Predict the p...

Question

Predict the position of the element in the periodic table satisfying the electronic configuration $(n - 1) d^{1} {n s}^{2}$ for $n = 4$ .

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Solution

Here outer most electron enters into the $3 d$ hence the element belongs to $d - b l o c k$ , number of group for $d - b l o c k$ element= no. of electrons in (n-1)orbital + no. of electrons in n orbital=2+1=3 hence, the element belongs to 3rd group. Here principal quantum number is equal to the period of the element hence the element belongs to 4th period.

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